Handle overflow when reversing integers

[krotname]

Motivation

• The existing ReverseInt.reverse(int) reversed the decimal string and used Integer.parseInt, which throws NumberFormatException when the reversed value exceeds 32-bit signed int bounds.

Description

• Replace string reversal + Integer.parseInt with parsing the reversed magnitude into a long using Long.parseLong after Math.abs((long) x), then restore the sign and clamp out-of-range results.
• The method now returns 0 when the reversed value is outside Integer.MIN_VALUE..Integer.MAX_VALUE while preserving previous behavior for in-range results.
• Updated src/main/java/other/ReverseInt.java to implement the long-based reversal and bound check.
• Extended src/test/java/other/ReverseIntTest.java with regression cases for a positive overflow (1534236469) and Integer.MIN_VALUE to ensure overflow returns 0.

Testing

• Ran the focused unit test with mvn -B -Dtest=other.ReverseIntTest test, and the test suite for that class passed (8 tests, 0 failures).
• Ran the full verification build with mvn -B verify, and the project completed successfully (599 tests run, 0 failures) with Checkstyle, PMD, and SpotBugs analysis passing.

---

Codex Task

[krotname]

Закрываю как superseded by #116: изменения перенесены в одну проверенную ветку, все review findings учтены; локальный mvn verify прошёл полностью.